romov3102
contestada

A pendulum with a mass of 0.100 kg was released. The string made a
7.0° angle with the vertical. The bob of the pendulum returns to its lowest point
every 0.10 s.
What is its period? What is its frequency?

Respuesta :

AL2006

The bob passes the lowest point twice during every complete swing.

The period of this pendulum is 0.2 seconds.

Frequency = 1/period

Frequency = 1/0.2 sec

Frequency = 5 Hz.  (A very very very short, fast pendulum.)

Note:  

The mass of the bob, the angle from the vertical (as long as it's small), the color of the string, and the day of the week have no effect on the period.  Only the length of the string has.

The period and the frequency of the pendulum with a mass of 0.100 kg will be 0.02 sec and 5Hz.

What is Simple harmonic motion?

Simple harmonic motion is periodic motion caused by a restoring force that is proportionate to the deviation from equilibrium.

Simple harmonic motion is periodic motion, but many other conditions are dependent.

During each entire swing, the bob goes through the lowest point twice. This pendulum has a period of 0.2 seconds.

The frequency is inversely proportional to the time period.

[tex]\rm f = \frac{1}{T} \\\\ f= \frac{1}{0.02} \\\\ f= 5 \ Hz[/tex]

Hence, the period and the frequency of the pendulum with a mass of 0.100 kg will be 0.02 sec and 5Hz.

To learn more about the simple harmonic motion, refer to the link;

https://brainly.com/question/17315536

#SPJ2

Otras preguntas