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Curly hair (C) is dominant over straight hair(c). a heterozygous curly haired woman marries a homozygous straight haired man. with respect to hair.
a. write the genotypes of man and woman
man:
woman;
b. what % of the children will have curly hair

Respuesta :

justicehall2002

The woman's genotype is Cc (she's heterozygous)

The man's genotype is cc (he's homozygous)

If you make a punnet square it'll look like this (I hope it works out)

    C     c

c  Cc   cc

c  Cc  cc

Since curly hair (C) is dominant, any genotype with a capital C will have curly hair. This means 2/4 or 50% of children will have curly hair

As in the given case, the man has genotype cc while the woman is having genotype Cc. In this case, the chances of having curly hair in children is 50%.

What is a Punnett square?

The Punnett square is a square diagram used to predict genotypes from a specific cross or breeding experiment.

As in the given case, the man has genotype cc while the woman is having genotype Cc.

In this case, the chances of having curly hair in children is 50% as per the Punnett square shown in the image attached.

Thus, the genotype of man and woman is cc and Cc respectively, while there are 50% chances that the children will have curly hair.

For more details regarding Punnett square, visit:

https://brainly.com/question/27984422

#SPJ2

Ver imagen VTshruti

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