Answer:
The correct option is 2.
Step-by-step explanation:
The given matrix multiplication is
[tex]\begin{bmatrix}2&4&-3\\ 6&1&0\end{bmatrix}\times \begin{bmatrix}-3&2\\ -2&3\\ -8&5\end{bmatrix}[/tex]
Order of matrix = Number of rows × Number of columns
Let [tex]A=\begin{bmatrix}2&4&-3\\ 6&1&0\end{bmatrix},B=\begin{bmatrix}-3&2\\ -2&3\\ -8&5\end{bmatrix}[/tex]
Order of matrix A = 2 × 3
Order of matrix B = 3 × 2
The order of product of two matrices is
[tex]A_{m\times n}\cdot B_{n\times k}=AB_{m\times k}[/tex]
It means
Order of product = Number of rows of first matrix × Number of columns of second matrix
Order of product = 2 × 2
[tex]A_{2\times 3}\cdot B_{3\times 2}=AB_{2\times 2}[/tex]
The dimensions of the product are 2 × 2. Therefore the correct option is 2.
