Answer:
The area of the logo is [tex]18.84\ ft^{2}[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a semicircle is equal to
[tex]A=\frac{1}{2}\pi r^{2}[/tex]
so
The area of the logo is equal to multiply by 3 the area of one semicircle
[tex]A=\frac{3}{2}\pi r^{2}[/tex]
we have
[tex]r=4/2=2\ ft[/tex] -----> the radius is half the diameter
substitute
[tex]A=\frac{3}{2}(3.14)(2)^{2}=18.84\ ft^{2}[/tex]
