The perimeter of the parallelogram with the vertices (-5, -1), (-2, -1), (-3, -4), and (-6, -4) is 12.32 units
How to determine the perimeter?
The vertices are given as:
(-5, -1), (-2, -1), (-3, -4), and (-6, -4)
Calculate the side lengths using:
[tex]L = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
So, we have:
[tex]L_1 = \sqrt{(-5 + 2)^2 + (-1 + 1)^2}[/tex]
[tex]L_1 = 3[/tex]
[tex]L_2 = \sqrt{(-2 + 3)^2 + (-1 + 4)^2}[/tex]
[tex]L_2 = \sqrt{10}[/tex]
L2 = 3.16
Opposite sides are equal.
So, the perimeter (P) is:
P = 2 * (L1 + L2)
This gives
P = 2 * (3 + 3.16)
Evaluate
P = 12.32
Hence, the perimeter of the parallelogram is 12.32 units
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