Answer:
7/10 × 6/9 = 42/90 = 7/15
Step-by-step explanation:
so theres 10 chips total.
on the first draw there 7 blue chips and a total of 10 chips of both colors
take one away from the 7 chips we have and get 6 over the 9 chips.
Answer: [tex]\dfrac{7}{15}[/tex]
Step-by-step explanation:
Given : The number of blue chips in the bag = 7
The number of gold chips in the bag = 3
Total number of chips : 7+3=10
Now, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip is given by :-
[tex]\dfrac{6\times7}{9\times10}=\dfrac{7}{15}[/tex]
Hence, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip [tex]=\dfrac{7}{15}[/tex]
