P=V^2/R
In the first case voltage is 100V, in the second case it is 110V
P1=10000/R
P2=12100/R
R=P1/10000
R=P2/12100
P1/10000=P2/12100
12100 . P1=P2 . 10000
Divide both by 100
P1 . 121=P2 . 100
Therefore Power in the second scenario is 21% less than the first one