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Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x.

Respuesta :

flappybird305

-10x^2-3x+4

Hope this helps

Answer:

quotient is [tex]10x^2+3x-4[/tex]

Step-by-step explanation:

[tex]\frac{-40x^3-12x^2+16x}{-4x}[/tex]

To find the quotient we divide each term by -4x

[tex]\frac{-40x^3}{-4x} =10x^2[/tex]

Negative and negative becomes positive.

[tex]\frac{-12x^2}{-4x} =3x[/tex]

[tex]\frac{-16x}{-4x} =-4[/tex]

[tex]\frac{-40x^3-12x^2+16x}{-4x}=10x^2+3x-4[/tex]

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