Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle is in the triangle. HELP PLEASE!!


Answer:
[tex]0.02[/tex]
Step-by-step explanation:
we know that
The probability that a point chosen randomly inside the rectangle is in the triangle is equal to divide the area of the triangle by the area of rectangle
Let
x-----> the area of triangle
y----> the area of rectangle
P -----> the probability
[tex]P=x/y[/tex]
Find the area of triangle (x)
[tex]A=(1/2)(5)(2)=5\ in^{2}[/tex]
Find the area of rectangle (y)
[tex]A=18*12=216\ in^{2}[/tex]
Find the probability P
[tex]P=5/216=0.02[/tex]