Answer:
The margin of error E that corresponds to a 95% confidence level is: [tex]E=0.03297[/tex]
Step-by-step explanation:
The propocion is [tex]p = 0.45[/tex]
The sample size [tex]n = 875[/tex]
95% confidence level
Level of significance = 1-level of confidence
Level of significance = 1-0.95 = 0.05
The formula for the error is:
[tex]E = Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}[/tex]
The value for [tex]Z_{0.05/2} =Z_{0.0250}= 1.96[/tex] according to the normal table
So:
[tex]E = 1.96\sqrt{\frac{0.45(1-0.45)}{875}}\\\\SE=0.03297[/tex]
