In what quadrant is the center of the following equation located: (x - 4)^2+ (y + 5)^2 = 16? Write 1, 2, 3, or 4.
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Answer:

Quadrant 4

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 4)² + (y + 5)² = 16 ← equation of circle in standard form

with centre (h, k) = (4, - 5) ← Quadrant 4

Answer:

Quadrant 4

Step-by-step explanation:

(x - 4)^2+ (y + 5)^2 = 16

This is a circle in the form

(x - h)^2+ (y +-k)^2 = r^2

The center is at (h,k)

(x - 4)^2+ (y - -5)^2 = 4^2

The center of our circle is at (4,-5) and the radius is 4

The x coordinate is positive and the y is negative.  This is in quadrant 4