Respuesta :
Answer:
Stay the same
Explanation:
First of all, let's find how the capacitance of the capacitor changes.
Initially, it is given by
[tex]C=\frac{\epsilon_0 A}{d}[/tex]
where
[tex]\epsilon_0[/tex] is the vacuum permittivity
A is the area of the plates
d is the separation between the plates
From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:
[tex]C' = \frac{1}{2}C[/tex]
The potential difference across the capacitor is given by
[tex]V= \frac{Q}{C}[/tex]
where
Q is the charge on the plates
C is the capacitance
We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:
[tex]V' = 2 V[/tex]
Now we can analyze the electric field between the plates of the capacitor, which is given by
[tex]E=\frac{V}{d}[/tex]
we said that:
- The voltage has doubled: V' = 2 V
- The distance between the plates has doubled: d' = 2 d
therefore, the new electric field will be
[tex]E'=\frac{2V}{2d}=\frac{V}{d}=E[/tex]
So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:
F = qE
Then the force on the particle will stay the same.
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force. The force on the particle will be the same.
what is parrallel plate capicitor ?
It is a type of capacitor in which two metal plates are arranged in such a way that they are connected in parallel and have some distance between them. A dielectric medium is a must in between these plates helps to stop the flow of electric current through it due to its non-conductive nature.
The capacitance between the two plates is given by,
[tex]C= \frac{\epsilon_0A}{d}[/tex]
The above relation shows that the capacitance between the two plates is inversely proportional to the distance of separation between them.
From the above condition if the distance between the plate is doubled the capacitance will be halved.
From the voltage capacitance relation. capacitance is inversely proportional to the voltage if the capacitance is halved the voltage will be doubled.
What is electric force?
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
it is the ratio of voltage to the distance between them.
[tex]\rm {E=\frac{V}{D} }[/tex]
If the voltage is double as well as the distance between the two plate is doubled.
[tex]\rm {E_2=\frac{2V}{2D} }[/tex]
[tex]\rm { E_2= E_1 }[/tex]
The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.
To learn more about the electric force refer to the link;
https://brainly.com/question/1076352
