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Given a right ?ABC, where AB = 4.5 cm, BC = 7.794 cm, and AC = 9 cm, sketch the triangle below, and find the measure m?C in degrees, rounded to the nearest tenth, if necessary. You may use sine, cosine, or tangent, it's your choice. Full credit requires a sketch and all sides of the triangle to be labeled with the lengths, and vertices to be labeled.

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Answer:

The measure of angle C is [tex]30\°[/tex]

The draw in the attached figure

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

The sine of angle C is equal to divide the opposite side to angle C by the hypotenuse

[tex]sin(C)=\frac{AB}{AC}[/tex]

substitute the values

[tex]sin(C)=\frac{4.5}{9}[/tex]

[tex]C=arcsin(\frac{4.5}{9})=30\°[/tex]

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