Respuesta :

you have to find the number of moles of hydrogen gas produced when zinc and hydrochloric acid reacted.  To do this you need to use the equation PV=nRT and solve for n.(n=PV/RT)
I would use 0.08206 atmL/molK For the gas constant so you need to convert 22°C into Kelvin, 748mmHg into atm, and 59.1mL into L.
22°C+273K=295K
748mmHgx(1atm/760mmHg)=0.984atm
59.1L=0.0591L
plugging everything in:
n=(0.0591Lx0.984atm)/(0.08206 atmL/molKx295K)
n=0.00240mol H₂
After finding the amount of hydrogen gas, you can find the volume of gas at STP by divide it by the molar volume of gas (22.4mol/L).
0.00240mol/22.4mol/L=1.07L H₂
The answer is 1.07L of hydrogen gas at STP was released from the reaction.
I hope this helps.  Let me know if there was anything that was unclear to you.
mahima6824soni

The volume of the H₂ at 0 °C and 1.00 atm pressure is 1.07L H₂.

What is volume?

Volume is the amount of space that a solid object covers.

Given that, the temperature is 0 °C

The pressure is 1.00 atm

The gas constant is 0.08206 atmL/molK

Change in temperature 22°C into Kelvin,

Change in pressure is 748mmHg into atm

22°C + 273K = 295K

748mmHg x (1atm / 760mmHg) = 0.984atm

59.1L = 0.0591 L

To calculate the volume, we will use the formula of ideal gas.

PV = nRT

n.(n = PV / RT)

Putting the values in the equation:

n = ( 0.0591L x 0.984atm) / (0.08206 atmL / molK x 295 K )

n = 0.00240mol H₂

By dividing the quantity of hydrogen gas by the molar volume of gas (22.4 mol/L), you may determine the volume of gas at STP.

0.00240mol / 22.4mol/L = 1.07L H₂

Thus, the volume of the H₂ is 1.07L H₂.

Learn more about volume, here:

https://brainly.com/question/20731189

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