Answer:
circle do not contains point (2√2 , -6)
Step-by-step explanation:
Equation of circle:
The centre-radius form of the circle equation is in the format
(x – h)² + (y – k)² = r²
with the centre being at the point (h, k) and the radius being "r"
Plug in values given the question to find the radius of circle
(4-0)² + (0 - 0)² = r²
r² = 16
r = √16
r = 4
To find coordinates(2√2 , -6) is in the circle
Simply plug in the x and y from your point (2√2 , -6)
If the the answer is greater than r², then the point lies outside of the circle else they are in the circle
(x – 0)² + (y – 0)² ≤ 16
((2√2)² – 0)² + ((-6)² – 0)² ≤ 16
8 + 36 ≤ 16
44 ≤ 16 False
Hence, (2√2 , -6) don't lie in or on the circle.
