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The concentration of H + ions at pH 6.
The concentration of H + can be deduced by the formula pH = - log H + ==> H + = 10 ^ (- pH)
H + = 10^-6 mol / l.
But, it is necessary to be careful in this case the, to deduce the concentration of the acid, one can only deuire it only from H + since here there is the pH of the water which intervenes (which is not negligible in this case)
Concentration of -OH at pH 6.
The concentration of -OH can be calculated from pOH: pOH = 14 - pH = 14 - 6 = 8
-OH = 10 (pOH) = 10^-8 mol / l.
or directly: -OH = 10^-14 / 10^-6 = 10^-8 mol / l
Here we can notice that the higher the concentration of H + is inversely proportional to -OH. Acidity and alkalinity are two opposite terms. More acidity is strong, and the lower the alkalinity and vice versa.
Calculation of the ratio H + / -OH:
This ratio allows us to determine which of these two ions is the most abundant and its importance in the environment.
We have H + and -OH from previous data so
H + / -OH = 10^-6 / 10^-8 = 10^2 = 100.
Thanks to this report, we can see that there are 100 times more H + than -OH. and this is quite logical since the pH 6 remains an acidic pH (less than 7) but which is still close to the neutrality.
The ratio of Hydrogen ion concentration to hydroxide ion concentration is 100
The concentration of H+ in solution of pH = 6 is?
pH of solution
This is the extent to which the hydrogen ion is present in the solution. It is also a measure of it's acidity of the solution.
The formula of this is given as
[tex]pH=-log[H^+][/tex]
substitute the value of pH and solve of the hydrogen ion concentration.
[tex]6=-log[H^+]\\\\H^+=10^-6\\H^+=1*10^-^6[/tex]
The hydrogen ion concentration is [tex]1*10^-6[/tex]
Concentration of OH-
This is basically the strength of the hydroxide ions in the solution.
The relationship between pH and pOH is
[tex]pH+pOH=14[/tex]
we know the pH of the solution
[tex]6+pOH=14\\pOH=14-6\\pOH=8[/tex]
The OH- ions in the solution can be calculated just the way we did for H+
[tex]pOH=-log[OH^-]\\8=-log[OH^-]\\OH^-=10^-8\\OH^-=1*10^-^8[/tex]
The OH- of the solution is [tex]1*10^-^8[/tex]
The ratio of H+ ions to OH- ions is
[tex]\frac{[H^+]}{[OH^-]}=\frac{1*10^-^6}{1*10^-^8}=100[/tex]
The data gotten from the above are
- pH of the solution = 6
- pOH of the solution = 8
- hydrogen ion concentration = [tex]1*10^-6[/tex]
- hydroxide ion concentration = [tex]1*10^-^8[/tex]
The ratio of hydrogen ion concentration to hydroxide ion concentration is 100
learn more on ratio here;
https://brainly.com/question/1781657
