Respuesta :
First let's put the equation into slope-intercept form...
y= mx + b
4x - 2y = -12
-2y = -4x - 12
y = 2x + 6
In this form, the y intercept is represented by b (in this case 6).
Now if we set y = to zero in the equation, that will give us the x intercept...
0= 2x + 6
-6 = 2x
-3 = x
So we have...
x Intercept = -3
y intercept = 6
y= mx + b
4x - 2y = -12
-2y = -4x - 12
y = 2x + 6
In this form, the y intercept is represented by b (in this case 6).
Now if we set y = to zero in the equation, that will give us the x intercept...
0= 2x + 6
-6 = 2x
-3 = x
So we have...
x Intercept = -3
y intercept = 6
x intercept is where the line crosses the x axis or where y=0
y intercept is where the line crosses the y axis or where x=0
x intercept
set y=0 and solve
4x-2(0)=-12
4x=-12
x=-3
(-3,0) is x intercept
y intercept
set x=0 and solve
4(0)-2y=-12
-2y=-12
y=6
(0,6)
xint=(-3,0)
yint=(0,6)
y intercept is where the line crosses the y axis or where x=0
x intercept
set y=0 and solve
4x-2(0)=-12
4x=-12
x=-3
(-3,0) is x intercept
y intercept
set x=0 and solve
4(0)-2y=-12
-2y=-12
y=6
(0,6)
xint=(-3,0)
yint=(0,6)