contestada

An organic liquid is a mixture of methyl alcohol (CH3OH) and ethyl alcohol (C2H5OH). A 0.220-g sample of the liquid is burned in an excess of O2(g) and yields 0.386 g CO2(g) (carbon dioxide). Set up two algebraic equations, one expressing the mass of carbon dioxide produced in terms of each reagent and the other expressing the mass of sample burned in terms of each reagent.What is the mass of methyl alcohol (CH3OH) in the sample?

Respuesta :

Edufirst

Answer: the mass of methyl alcohol (CH3OH) in the sample is 0.0641 g

Explanation:

1. Preliminars;

  • Mass  of CH₃ OH: M
  • Mass of C₂H₅OH: E
  • Molar mass of CH₃ OH: 32.04 g/mol
  • Molar mass of C₂H₅OH: 46.07 g/mol
  • Molar mass of CO₂: 44.01 g/mol
  • Molar mass equation: molar mass = mass in grams / number of moles

2. Algebraic equation # 1: mass of sample burned in terms of each reagent.

  • M + E = 0.220 ------ (1)

3. Algebraic equation # 2: mass of carbon dioxide produced in terms of each reagent.

a) Combustion of methyl alcohol

  • 2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)
  • 2 mol CH₃OH → 2 mol CO₂
  • 2 × 32.04 g CH₃OH → 2 × 44.01 g CO₂
  • Mass of CO₂ produced from M grams of CH₃OH = M / 32.04 × 44.01 = 1.374 M

b) Combustion of ethyl alcohol

  • C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g)
  • 1 mol C₂H₅OH → 2 mol CO₂
  • 46.07 g CH₃OH → 2 × 44.01 g CO₂
  • Mass of CO₂ produced from E grams of C₂H₅OH = E / 46.07 × 88.02 = 1.911 E

c) Mass of CO₂ (g) obtained, in terms of each reagent

  •     1.374 M + 1.911 E = 0.386 ----- (2)

4) System of equations

  •        M   +         E = 0.220 ------ (1)
  • 1.374 M + 1.911 E = 0.386 ----- (2)

5) Solution

  • From equation (1): E = 0.220 - M
  • Substituting in equation (2): 1.374 M + 1.911 (0.220 - M) = 0.386
  • 1.374 M + 0.4204 - 1.911 M = 0.386
  • - 0.537 M = - 0.0344
  • M = 0.0344 / 0.537 = 0.0641 g

Answer:  the mass of methyl alcohol (CH3OH) in the sample is 0.0641 g

mahima6824soni

Methyl alcohol also known as methanol is a colorless liquid. The mass of carbon dioxide is 0.386 and the mass of methyl alcohol is 0.0641 g.

What are alcohols?

Alcohols are organic compounds in which a carboxyl group is attached to the carbon atom.

Given,

Molar mass of CH₃OH is 32.04 g/mol

Molar mass of C₂H₅OH is 46.07 g/mol

Molar mass of CO₂ is 44.01 g/mol

The first algebraic equation is

M(CH₃OH)+ M(C₂H₅OH) = 0.220

The second algebraic equation is

a. The combustion of CH₃OH  :

[tex]2CH_3OH(l) + 3O_2(g) = 2CO_2(g) + 4H_2O(g)[/tex]

[tex]2\; mol\; CH_3OH = 2 mol CO_2\\\\ 2 \times \; 32.04\; g\; CH_3OH = 2 \times 44.01\; g\; CO_2[/tex]

Mass of CO₂ produced from M grams of CH₃OH = [tex]\dfrac{M}{32.04}\times 44.01 = 1.374\; M[/tex]

b. The combustion of C₂H₅OH:

[tex]C_2H_5OH(l) + 3O_2(g) = 2CO_2(g) + 3H_2O(g)\\\\ 1 mol C_2H_5OH = 2 mol CO_2\\\\ 46.07 g CH_3OH = 2 \times44.01\; g\; CO_2[/tex]

Mass of CO₂ produced from E grams of C₂H₅OH =[tex]\dfrac{M(C_2H_5OH)}{46.07} \times88.02 = 1.911\; E[/tex]

c. Mass of carbon dioxide is   1.374 M + 1.911 E = 0.386

Thus, the calculation

1.374 M + 1.911 (0.220 - M) = 0.386

1.374 M + 0.4204 - 1.911 M = 0.386

- 0.537 M = - 0.0344

M = 0.0344 / 0.537 = 0.0641 g

The mass of methyl alcohol is 0.0641 g

Thus, the mass of carbon dioxide is 0.386

The mass of methyl alcohol is 0.0641 g

Learn more about alcohol, here:

https://brainly.com/question/4212138

Otras preguntas