What are the solutions to the system of equations?
y=x^2+5x+6,
y=3x+6

A. (0, 6) and (−2, 0)
B. (−3, 0) and (0, 6)
C. (−3, 0) and (−2, 0)
D. (0, −3) and (6, 0)

Respuesta :

Answer:

A. (0, 6) and (−2, 0)

Step-by-step explanation:

The given equations are:

[tex]y=x^2+5x+6[/tex]

and

[tex]y=3x+6[/tex]

We equate the two equations to find their point of intersection;

[tex]x^2+5x+6=3x+6[/tex]

We equate everything to zero to get;

[tex]x^2+2x=0[/tex]

[tex]x(x+2)=0[/tex]

[tex]x=0,x=-2[/tex]

When x=0, y=3(0)+6=6

One solution is;

(0,6)

When x=-2,

y=3(-2)+6=0

Another solution is;

(-2,0)

you can just plug in the x’s to find the y’s.

for example, you can plug in (0,6) into y=x^2+5x+6 by placing the 0 from the point where the x’s are to see if it gives you 6 (the ‘y’ term in the point)

this would look like y=(0)^2+5(0)+6

when you type this in, if it gives you 6 as the answer, then (0,6) is a solution