Respuesta :
Answer:
A. (0, 6) and (−2, 0)
Step-by-step explanation:
The given equations are:
[tex]y=x^2+5x+6[/tex]
and
[tex]y=3x+6[/tex]
We equate the two equations to find their point of intersection;
[tex]x^2+5x+6=3x+6[/tex]
We equate everything to zero to get;
[tex]x^2+2x=0[/tex]
[tex]x(x+2)=0[/tex]
[tex]x=0,x=-2[/tex]
When x=0, y=3(0)+6=6
One solution is;
(0,6)
When x=-2,
y=3(-2)+6=0
Another solution is;
(-2,0)
you can just plug in the x’s to find the y’s.
for example, you can plug in (0,6) into y=x^2+5x+6 by placing the 0 from the point where the x’s are to see if it gives you 6 (the ‘y’ term in the point)
this would look like y=(0)^2+5(0)+6
when you type this in, if it gives you 6 as the answer, then (0,6) is a solution