Respuesta :
Answer:
[tex]\large\boxed{p\leq-0.925}[/tex]
Step-by-step explanation:
[tex]\dfrac{7}{10}\geq1\dfrac{5}{8}+p\qquad\text{convert to the decimal}\\\\0.7\geq1.625+p\qquad\text{subtract 1.625 from both sides}\\\\-0.925\geq p\to p\leq-0.925[/tex]
