What is the surface area of the figure shown?

square = 8×8=64
rectangles =11×8=88 88×4=352
triangles=8×8=64÷2=32×4=128
64+352+128=544cm²
Answer:
The surface area of the figure = 544 cm²
Step-by-step explanation:
From the figure we can see that a cuboid and square pyramid
Total surface area = (Area of cuboid + Area of pyramid)
To find the area of cuboid
Area of cuboid = base area + area of 4 lateral face
Base area = side * side = 8 * 8 = 64 cm²
Area of 4 lateral face = 4 *(area of one rectangle) = 4 *(11*8) = 352 cm²
Area of cuboid = 64 + 352 = 416 cm²
To find the area of square pyramid
Slant height of pyramid = 8 cm
Base = 8 cm
Area of pyramid = 4 *(area of one triangle face) = 4(8*8/2) = 128 cm²
To find the total surface area
Total surface area = (Area of cuboid + Area of pyramid)
= 416 + 128 = 544
Therefore the surface area of the figure = 544 cm²