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kudzordzifrancis

ANSWER

[tex]y = 5x + 6[/tex]

EXPLANATION

The given equation is

[tex]y = 5x - 7[/tex]

The slope of this line is

[tex]m = 5[/tex]

Any line parallel to this line also has the same slope.

If the parallel line passes through (1,11),

then, it's equation is given by:

[tex]y-y_1=m(x-x_1)[/tex]

Substitute the slope and point to get,

[tex]y - 11 = 5(x - 1)[/tex]

[tex]y = 5x - 5 + 11[/tex]

[tex]y = 5 x + 6[/tex]

is the required equation.

zainebamir540

Answer:

y = 5x+6 is equation of line that is parallel to y = 5x-7 and passing through (1,11).

Step-by-step explanation:

We have given a equation of line and a point.

y = 5x-7 (x,y) = (1,11)

We have to find equation of line that is parallel to given equation of line and passing through given point.

y-y = m(x-x) is point-slope form of equation of line where m is slope of line.

Since, we know that parallel line have equal slope of line.

Given equation has slope equal to 5.

Parallel line also has slope equal to 5.

m = 5

Putting values in point-slope form of equation , we have

y-(11) = 5(x-1)

y-11 = 5x-5

y = 5x-5+11

y = 5x+6 is equation of line that is parallel to y = 5x-7 and passing through (1,11).

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