[tex]3p^4 (4p^4 + 7p^3 + 1) \\ \\ 3p^4 \times 4p^4 + 3p^4 \times 7p^3 + 3p^4 \\ \\ 3 \times 4p^4p^4 + 3p^4 \times 7p^3 + 3p^4 \\ \\ 3 \times 4p^{4 + 4} + 3p^4 \times 7p^3 + 3p^4 \\ \\ 3 \times 4p^8 + 3p^4 \times 7p^3 + 3p^4 \\ \\ 12p^8 + 3p^4 \times 7p^3 + 3p^4 \\ \\ 12p^8 + 3 \times 7p^4p^4 + 3p^4 \\ \\ 12p^8 + 3 \times 7p^{4 + 3} + 3p^4 \\ \\ 12p^8 + 3 \times 7p^7 + 3p^4 \\ \\ 12p^8 + 21p^7 + 3p^4[/tex]
The answer is: 12p^8 + 21p^7 + 3p^4.
