[tex]y = 3x^2+6x-5[/tex]
For a parabola [tex]ax^2+bx+c[/tex] the vertex's x equals:
[tex] \frac{-b}{a} [/tex]
[tex]a = 3, b =6[/tex]
[tex]x = \frac{-6}{2*3} [/tex]
refine:
[tex]x = -1[/tex]
Plug in x = -1 to find the y value :
[tex]y=3(-1)^2+6(-1)-5[/tex]
refine :
[tex]y = -8[/tex]
Therefore the parabola vertex is :
[tex](-1,-8)[/tex]
if a < 0 , then the vertex is a maximum value
if a > 0, then then vertex is a minimum value
a=3
Therefore [tex](-1,-8) [/tex] minimum
hope this helps!
