an airport charges an additional fee for a piece of luggage that weighs more than 50 lbs write an inequality that shows the weight Michaels suitcase can be X without having to pay for the extra fee​

Respuesta :

MsRay

Answer:

X ≤ 50

Step-by-step explanation:

Since the additional fee for a piece of luggage is only charged if it weighs more than 50 lbs, than Michael's suitcase weight must be less than, or equal to, 50 lbs.  Using 'X' as the weight of Michael's suitcase in pounds:

X ≤ 50

'X' is less than or equal to 50 lbs

You can use the fact that the term "more than" can be a restriction whose opposite can be written as to "less than or equal to" based on the given condition.

The inequality that models the given problem is given by

[tex]x \leq 50[/tex] (where 50 is denoting 50 pounds)

How to form the inequality that models the problem?

We can convert the descriptions to mathematical symbols.

Since the additional cost is applied only when the weight is more than 50 lbs, thus, for not paying any extra fees, we need the weight to be not more than 50.

When weight is not more than 50, then it may be either 50 or less than 50.

And since weight is denoted by x, thus

[tex]x \leq 50 \: \rm lbs[/tex] is the inequality needed. It shows that the weight x should be either less or equal to 50 lbs.

The signs < and = when mixed is written as ≤

Thus,

The inequality that models the given problem is given by

[tex]x \leq 50[/tex]

Learn more about inequalities here:
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