Respuesta :
Answer:
ZnCl₂ + 2NaOH → Zn(OH)₂↓ + 2NaCl
Explanation:
- ZnCl₂ reacts with NaOH to produce a white precipitate of Zn(OH)₂ and NaCl.
- The net ionic equation of the reaction is:
ZnCl₂ + 2NaOH → Zn(OH)₂↓ + 2NaCl
Answer:
The met ionic equation is zero.
Explanation:
Zn²⁺ 2Cl⁻ + 2Na⁺ + 2OH⁻ → Zn²⁺ + 2OH⁻ + 2Na⁺ + 2Cl⁻
We'll then cancel out ions that are present in both reactant and product phase.
Zn²⁺ will cancel out each other from both sides.
2Cl⁻ will cancel out each other from both sides.
2Na⁺ will cancel out each other from both sides.
2OH⁻ will cancel out ewch other from both sides.
Leaving the net ionic equation zero(0).