Answer:
Cu + NO₃⁻ + 2H⁺ → Cu²⁺ + NO₂⁻ + H₂O.
Explanation:
- For the two half reactions:
Cu → Cu²⁺ + 2e⁻ (1)
NO₃⁻ + 2e⁻ + 2H⁺ → NO₂⁻ + H₂O (2)
- To obtain the final balanced equation, we sum the two half reactions that the 2e are omitted in the both sides of the two reactions.
So, the final balanced equation is:
Cu + NO₃⁻ + 2H⁺ → Cu²⁺ + NO₂⁻ + H₂O.
