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A sample of oxygen gas occupies 3.60 liters at a pressure of 1.00 atm. If temperature is held constant, what will be the volume of the oxygen gas at a pressure of 2.50 atm?


0.694 L

1.44 L

4.35 L

9.20 L

Respuesta :

chloepenney
P1V1=P2V2
(1.00atm)(3.60L)=(2.50atm)V
3.60=(2.50atm)V
3.60/2.50=V
1.44L=V

Answer:

The volume of O2 gas = 1.44 L

Explanation:

Given:

Initial volume of O2 gas, V1 = 3.60 L

Initial pressure, P1 = 1.00 atm

Final pressure, P2 = 2.50 atm

To determine:

Final volume of O2 gas, V2

Explanation:

Based on the ideal gas equation

[tex]PV = nRT\\[/tex]

where n = moles of gas

R = gas constant, T = temperature

At constant T, the above equation becomes:

PV = constant

[tex]i.e.\ P1V1= P2V2\\\\V2 = \frac{P1V1}{P2} = \frac{1.00atm*3.60 L}{2.50atm} =1.44\ L[/tex]

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