Question 1:
The area of flag b is the greatest.
Explanation:
Area of triangle = [tex]\frac{1}{2}base*height[/tex]
Area of parallelogram = base * height
For flag A:
It is a triangle with base = b and height = a
Area of flag A = [tex]\frac{1}{2}a*b[/tex] square units
For flag B:
It is a parallelogram with base = a and height = b
Area of flag B = a*b square units
For flag C:
It is a triangle with base = b and height = a
Area of flag C = [tex]\frac{1}{2}a*b[/tex] square units
From the above, we can conclude that the area of the parallelogram (flag B) is the greatest
Question 2:
The perimeter of flag C is shorter than that of flag A
Explanation:
Perimeter is the sum of the three sides of the figure
For flag C:
The three sides are given as a, b and c
Therefore, perimeter of flag c = a + b + c units
For flag A:
We are given two sides as b and c and we are given that the height is a
We know that in the given flag, the third side (the unknown slant one) will be longer than the height of the height of the triangle
Therefore, the third side = a + k where k is a constant
Therefore, perimeter of flag A = a + b + c + k units
From the above, we can conclude that the perimeter of flag C is shorter
Hope this helps :)
