Answer: The third option.
Step-by-step explanation:
You can write the following equation of the line of the exercise:
[tex]y=mx+b[/tex]
Where:
y=s
x=r
m is the slope.
b is the intersection of the line with the y-axis (Identified as "s").
The slope can be calculated as following:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{12-11}{2-1}=1[/tex]
As you can see in the graph, when r=0, s=10, therefore, the intersection of the line with the y-axis (Identified as "s") is:
b=10
Therefore, the equation is:
[tex]y=x+10[/tex]
Then, you must look for a graph that has a slope 1 and that the line intersects the y-axis (Identified as "s") at 10 (r=0, s=10)
This would be the third graph.
