For this case we have to:
[tex]AB = 8[/tex]is the height of the triangle.
[tex]AC = 12[/tex] is the base of the triangle
We want to find the value of angle B, so we have:
[tex]Tangent \ (B) = \frac {Cathet \ opposite} {Cathet \ adjacent}\\Tangent \ (B) = \frac {12} {8}\\Tangent \ (B) = \frac {3} {2}\\B = arc \ tangent (\frac {3} {2})\\B = 56.30993247 \ grades[/tex]
Rounding:
[tex]B = 56.3\ degrees[/tex]
ANswer:
[tex]B = 56.3\ degrees[/tex]
