Answer:
[tex]\Rightarrow x=-\frac{6}{7}[/tex] is the required result.
Step-by-step explanation:
We have been given an equation:[tex]a-bx=cx+d[/tex] (2)
And [tex]x=\frac{a-d}{b+c}[/tex]
And an equation:[tex]5-6x=8x+17[/tex] (1)
We will compare this equation (1) by (2) we get:
[tex]a=5,b=6,c=8,d=17[/tex]
So, according to the solution of equation (2) we will get the solution of equation (1) we get:
[tex]x=\frac{5-17}{6+8}[/tex]
[tex]\Rightarrow x=\frac{-12}{14}[/tex]
[tex]\Rightarrow x=-\frac{6}{7}[/tex] is the required result.
Answer:
[tex] x = - \frac{6} {7} [/tex]
Step-by-step explanation:
We are given the following algebraic expression and we are to solve it for x using the general solution:
[tex] 5 - 6x = 8x + 17 [/tex]
Rearranging the given expression by grouping the like terms together to get:
[tex] 5 - 17 = 8x + 6x [/tex]
[tex] 14x = -12 [/tex]
[tex] x=- \frac{12} {14} [/tex]
[tex] x = - \frac{6} {7} [/tex]
