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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

What are the domain and range of the function?

f(x) = √x + 6

PLEASE HELP ASAP CORRECT ANSWER ONLY PLEASE What are the domain and range of the function fx x 6 class=

Respuesta :

Answer:

  • Domain: [tex][0, \infty)[/tex].
  • Range: [tex][6, \infty)[/tex].

Step-by-step explanation:

[tex]\sqrt{x}[/tex] is defined only for non-negative values. So is the case when you add [tex]\sqrt{x}[/tex] to 6. The function [tex]f(x)[/tex] is defined for all non-negative values of [tex]x[/tex]. That is: [tex]x \in [0, \infty)[/tex]. 0 is allowed, hence the square bracket on the left end. Hence the domain of this function.

[tex]\sqrt{x}[/tex] gives values ranging from 0 to infinity. When you add 6 to [tex]\sqrt{x}[/tex], you should expect values no less than 6. That is: [tex][6, \infty)[/tex]. 6 is included. Hence the range of this function.

Answer: (C) Domain [0, ∞)

                     Range [6, ∞)

Step-by-step explanation:

Domain is the x-values.  There is a restriction on x in the given problem because the term inside the square root must be greater than or equal to zero.  So, x ≥ 0

Range is the y-values.  These values are determined by the domain.

Since x ≥ 0,

then y ≥ 0 + 6  

 ⇒   y ≥ 6