the diagram shows a right angled triangle. its hypotenuese is (x+4) cm while tge lengths of the otger two sides are x cm and (2x-y) cm respectively. If the perimeter of the triangle is 24 cm, find the value of x and of y with the condition x> y
H^2=p^2+b^2 (x+4)^2=x^2+(-2x+20)^2 From here you can calculate value of x and y x^2+16+8x=5x^2-80x+400 4x^2-88x+384 =x^2-22x+96 you use quadratic formula to calculate x and y Remember greatest value should be x and smallest should be y as the conditions given above
