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Examine the forces acting on a car on a ramp. Select the forces or force components that need to be added together to calculate the net force in the x-direction. Check all that apply.

FN
–Ff
–Fg
Fg (cos 15°)
Fg (sin 15°)

Respuesta :

The answer is -Ff & Fg(sin 15°)

Answer:

Frictional force, [tex]-F_f[/tex] and Weight, [tex]F_g\ sin(15^0)[/tex]

Explanation:

The attached figure shows the free body diagram of a car placed at the ramp. The net forces acting the car :

1. Normal force

2. Weight, mg

3. Frictional force

But the forces acting on the car in x- direction or horizontal path are frictional force (which acts in opposite direction of the motion) and of its weight.

So, the correct options are :

  • Frictional force, [tex]-F_f[/tex]
  • Weight, [tex]F_g\ sin(15^0)[/tex]
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