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A particle starts with initial speed v1 and travels along a straight line with an acceleration a = cv m/s2, where v is in m/s and c is a positive constant. what is the distance traveled by the particle before its speed reaches v2?

Respuesta :

Explanation :

It is given that,

initial speed of particle is [tex]v_1[/tex]

final speed of particle is [tex]v_2[/tex]

acceleration of particle is [tex]a=cv[/tex]

Let s is the distance traveled by particle before it reaches  [tex]v_2[/tex]

Now, using equation of motion as :

[tex]v^2_2-v^2_1=2as[/tex]

so, [tex]s=\frac{v^2_2-v^2_1}{2a}[/tex]

[tex]s=\frac{v^2_2-v^2_1}{2cv}[/tex]

Hence, the distance covered by the particle is [tex]s=\frac{v^2_2-v^2_1}{2cv}[/tex]                    

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