[tex]a_{n}[/tex] = 12 + (- 6)(n - 1 )
This is an arithmetic sequence with n th term
[tex]a_{n}[/tex] = [tex]a_{1}[/tex] + (n - 1)d
here d = - 6 - 0 = 0 - 6 = 6 - 12 = -6 and [tex]a_{1}[/tex] = 12, hence
[tex]a_{n}[/tex] = 12 + (- 6)(n - 1)
use this formula to find the 30 th term
[tex]a_{30}[/tex] = 12 + (- 6 × 29) = 12 - 174 = - 162