What is the length of the hypotenuse of the triangle?

Essentially, we just use the pythagorean theorem to solve:
7^2 + 3^2 = c^2
49 + 9 = c^2
58 = c^2
c = sqrt 58
The answer is Option D.
pythagorean theorem
for a right triangle with legs (2 sides next to the the right angle) length a and b, and hyptonuse (longest side oposite right angle) is c
[tex]a^2+b^2=c^2[/tex]
we can see that the legs are 3cm and 7cm
so a=3 and b=7 (you can do a=7 and b=3 but it doesn't matter)
[tex]a^2+b^2=c^2[/tex]
[tex]3^2+7^2=c^2[/tex]
[tex]9+49=c^2[/tex]
[tex]58=c^2[/tex]
sqrare root both sides
[tex]\sqrt{58}=c[/tex]
[tex]c=\sqrt{58}[/tex]
answer is 4th option