-x^2 + 3x + 40
The 2 numbers in the parentheses must be 5 and 8 to get the 3x and 40 and there also must be a negative outside the parentheses
so its
- (x^2 - 3x - 40)
= -(x + 5)(x - 8) answer
Option D
Answer:
D.Negative left parenthesis x plus 5 right- parenthesis left- parenthesis x-minus 8 right parenthesis.
Step-by-step explanation:
We are given that an expression
[tex]-x^2+3x+40[/tex]
We have to factorize the given expression.
The given expression can be write as
[tex]-(x^2-3x-40)[/tex]
[tex]-(x^2-8x+5x-40)[/tex]
Taking out common value
[tex]-(x(x-8)+5(x-8))[/tex]
Now, taking common factor out
[tex]-(x+5)(x-8)[/tex]
Hence, the expression in factorize form is given by
[tex]-(x+5)(x-8)[/tex]
Option D is true.
