Answer:
Question 1). table 1
Question 2). Option B
Step-by-step explanation:
Question 1). If we analyse graph 1 we find a straight line of which we have to find the equation first.
Since the equation of any line is represented by y = mx + c
where m = slope of the line
c = y- intercept
Graph 1 shows line has no y-intercept (passing through origin) so c = 0
and the equation will be y = mx
Now slope m = [tex]\frac{y-y'}{x-x'}[/tex]
In graph 1 line is passing through two points (3, 1) and (0, 0).
Therefore m = [tex]\frac{1-0}{3-0}=\frac{1}{3}[/tex]
Finally equation of the line is [tex]y=\frac{1}{3}x[/tex]
or x - 3y = 0
Now we plug in the values of x and y from graph 2, table 1
For (-3, -1)
-3 - (3)(-1) = -3 + 3 = 0
So table 1 is the answer.
Question 2). In this question we have to describe the pattern showing the relation between x and y.
In other words we have to find the slope of the line which describes flow of water y in x hours.
Slope = [tex]\frac{y-y'}{x-x'}[/tex]
Here the line is passing through two points (0, 0) and (1, 2)
By putting the values in the formula of slope
[tex]m= \frac{2-0}{1-0}=2[/tex]
So water level in the cup is increasing by 2 inches per hour.
Option B. is the answer.