Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq)+2Ag(s)

Respuesta :

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

Answer : The expression for equilibrium constant for the given reaction is,

[tex]K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}[/tex]

Explanation :

The given balanced chemical reaction is,

[tex]2Ag^+(aq)+Zn(s)\rightleftharpoons Zn^{2+}(aq)+2Ag(s)[/tex]

In the expression of equilibrium constant, only aqueous and gaseous substances are included. pure liquids and solids are not included.

Thus, the expression for equilibrium constant for the given reaction is,

[tex]K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}[/tex]