The sum of two consecutive odd interferes equals 12. What are they?

The sum of two consecutive odd integers equals 12
Let x represents the first odd integer
x+2 represents the second odd integer
Sum of first and second integer is x + (x+2)
The sum of two consecutive odd integers equals 12
So x +(x+2) = 12
x + x + 2= 12
2x + 2 = 12
Subtract 2 on both sides
2x = 10
Divide both sides by 2
x= 5
First odd integer = 5
second odd integer = x+2 = 5+2 = 7
Two odd integers are 5 and 7
Answer:
The two consecutive integers are 5 and 7
Step-by-step explanation:
We know that the sum of two consecutive odd integers is equal to 12.
Assuming the first integer to be x and the second consecutive integer to be x+2, we can make the following equation:
[tex]x+(x+2)=12[/tex]
[tex]x+x+2=12\\\\2x+2=12\\\\2x=12-2\\\\2x=10\\\\x=\frac{10}{2} \\\\x=5[/tex]
The first integer is 5 so the second integer will be:
[tex]x+2=5+2=7[/tex]
So the two consecutive integers are 5 and 7.