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Mustafa is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satellite can be modeled by (y+2)^2=9(x-2) where x and y are modeled in inches. He realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite?
(4.25, –2)
(4.25, 0)
(4.25, 2)
(4.25, 4)

Respuesta :

allisonmw8888

(4.25, -2) is the focus point

Answer:

A. (4.25, –2)

Step-by-step explanation:

We are given that,

The shape of the satellite is modeled by the function, [tex](y+2)^2=9(x-2).[/tex]

Since, the equation of a parabola is [tex](y-k)^2=4p(x-h)[/tex] .

So, on comparing, we have,

h= 2, k= -2 and [tex]4p=9[/tex]

i.e. h= 2, k= -2 and [tex]p=\frac{9}{4}[/tex]

As, the focus point is (h+p,k).

So, we get,

The focus point = [tex](2+\frac{9}{4},-2)[/tex]

i.e. The focus point = [tex](\frac{17}{4},-2)[/tex]

i.e. The focus point = (4.25,-2)

Hence, the focus point of the satellite is (4.25,-2).

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