Respuesta :

[tex]f(x)=x^2-6x+9=(x-3)^2[/tex]


This a perfect square so the x-axis is a tangent at x=3


The correct answer is C


See graph

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Given function is f(x) = x² -6x +9.

It is a quadratic function whose graph is an upward open parabola.

The zero(s) of the given function would be at x-intercepts of the graph i.e. y = 0.

It means 0 = x² -6x +9

We can solve this quadratic equation using factorization as follows:-

0 = x² -6x +9

0 = x² -3x -3x +9

0 = x(x-3) -3(x-3)

0 = (x-3)(x-3)

Therefore, x = 3 with multiplicity two.

Hence, option C is correct, i.e. The graph of the function touches the x-axis at x = 3.