Average speed is defined as ratio of total distance covered and total time
now we will have
[tex]d_1 = 4 km[/tex]
[tex]t_1 = 32 min[/tex]
[tex]d_2 = 2 km[/tex]
[tex]t_2 = 22 min[/tex]
[tex]d_3 = 1 km[/tex]
[tex]t_3 = 16 min[/tex]
now total distance moved is
[tex]d = d_1 + d_2 + d_3[/tex]
[tex]d = 4 + 2 + 1 = 7 km[/tex]
total time is given as
[tex]t = 32 min + 22 min + 16 min[/tex]
[tex]t = 70 min[/tex]
now average speed is given as
[tex]v_{avg} = \frac{d}{t}[/tex]
[tex]v_{avg} = \frac{7}{70} = 0.1 km/min[/tex]
so its average speed is 0.1 km per minute
Answer:
[tex]0.1 \ km/min[/tex]
Explanation:
We know speed , s is given by [tex]s=\dfrac{distance}{time}.[/tex]
NOW,
Average speed , S is given by:
[tex]S=\dfrac{total \ distance\ covered}{total\ time \ taken }[/tex]. .....eqn 1.
Total distance covered , [tex]D=4+2+1 \ km=7 \ km[/tex].
Total time taken, [tex]T=32+22+16\ min=70 \ min.[/tex]
Putting these values in equation 1.
We get,
[tex]S=\dfrac{7}{70} \ km/min=0.1\ km/min.[/tex]
