Math help questions, will reward xoxo thank you !


AB = 10 → C and BC = 10 → A
to calculate the lengths use the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 3, - 4) and (x₂, y₂ ) = (5, 2 )
AB = √(5 + 3 )² + (2 + 4 )² = √(64 + 36 ) = √100 = 10 → C
with (x₁, y₁ ) = (5, 2 ) and (x₂, y₂ ) = (11, - 6 )
BC = √(11 - 5 )² + (- 6 - 2 )² = √(36 + 64 ) = √100 = 10 → A
Distance formula: d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
AB:
1- Substitute A (-3, -4) for (x₁, y₁) and B (5, 2) for (x₂, y₂)
2- Plug them in the formula: AB = √ (5 - (-3))² + (2 - (-4))²
3- Solve:
√ (5 + 3)² + (2 + 4)² =
√ 8² + 6² =
√ 64 + 36 =
√ 100 =
10
AB = 10
What is AB?
C. 10
BC:
1- Substitute B (5, 2) for (x₁, y₁) and C (11, -6) for (x₂, y₂)
2- Plug them in the formula: BC = √ (11 - 5)² + (-6 - 2)²
3- Solve:
√ 6² + (-8)² =
√ 36 + 64 =
√ 100 =
10
What is BC?
A. 10