Karen drops a 2.0 kg rock from the top of a mountain. Determine the distance the rock travels after falling for 3 seconds assuming it has reached free fall and given the gravitational acceleration of 9.8 m/sec2 downward. [HINT: Distance=(0.5)*(acceleration)*(time2)]

Respuesta :

Um...Is it 29.4m? I'm guessing, since, there's 3 seconds and it's at 9.8m/sec downward, so,

9.8 x 3 = 29.4m

Explanation:

The data given is as follows.

     mass = 2.0 kg

     time = 3 seconds

 gravitational acceleration = [tex]9.8 m/s^{2}[/tex]

Calculate the distance traveled by the rock when it falls is as follows.

          [tex]Distance = \frac{1}{2} \times acceleration \times time^{2}[/tex]

                                 = [tex]\frac{1}{2} \times 9.8 m/s^{2} \times (3 second)^{2}[/tex]

                                 = [tex]\frac{1}{2} \times 9.8 m/s^{2} \times 9 second^{2}[/tex]

                                 = 44.1 m

Therefore, the distance traveled by rock is 44.1 meter.