contestada

A compound of two chemicals is mixed in a ratio of 3:12 if there are 45L of the compound how much of each chemical is in the mixture

Respuesta :

3x+12x=45

15x=45

x=3

the first chemical is 3*3 or 9 L

the second chemical is 12*3 = 36 L

Limosa

Answer:

We need 9L from one chemical and 12L from the other.

Step-by-step explanation:

What 3:12 means is that if you add 3L from one chemical(lets say A chemical) then you will have to add 12L from the other chemical (lets say B chemical) to make the compound.

Now Lets take that you added [tex]x[/tex]L of chemical A to make 45L of the compound.

So if add 3L from chemical A you have to add 12L of chemical B, so if you add [tex]x[/tex]L of A then how many liters of B do you need?

⇒[tex]\frac{12}{3} *x[/tex]

=[tex]4x[/tex]

So you will need [tex]4x[/tex]L of chemical B.

Now we can write an equation for the total amount of compound B as,

⇒[tex]x+4x=45[/tex]

[tex]5x=45[/tex]

[tex]x=9[/tex]

Therefore,

We need 9L of chemical A, and

We need 36L of chemical B