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a student is pushing a 50kg cart, with a force of 600N. another student measures the speed of the cart, and finds that the cart is only accelerating at 3/m2. how much friction must be acting on the cart.(hint draw a diagram showing the cart, and the two forces acting on it.

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Answer:

frictional force acting on the cart 450 N.

Given:

mass of cart = 50 kg

acceleration = 3 [tex]\frac{m}{s^{2} }[/tex]

To find:

Frictional force = ?

Formula used:

F - [tex]F_{k}[/tex] = 600 N

F = ma

[tex]F_{k}[/tex] = frictional force

Solution:

Force on the block is given by,

F - [tex]F_{k}[/tex] = 600 N

F = ma

[tex]F_{k}[/tex] = frictional force

[tex]F_{k}[/tex] = 600 - m a

[tex]F_{k}[/tex] = 600 - (50 × 3)

[tex]F_{k}[/tex] = 600- 150

[tex]F_{k}[/tex] = 450 N

According to the given data the frictional force acting on the cart 450 N.

Ver imagen Branta
Lanuel

The amount of friction which must be acting on the cart is 450 Newton.

Given the following data:

  • Mass of cart = 50 kg
  • Force = 600 Newton
  • Acceleration = 3 [tex]m/s^2[/tex]

To find how much friction must be acting on the cart, we would Newton's Second Law of Motion:

[tex]Net\; force = Force + Frictional\; force[/tex]    ....equation 1.

Rearranging the eqn, we have:

[tex]Frictional\; force = Force - Net\; force[/tex]    ....equation 2.

To solve for the net force:

[tex]Net \;force = mass \times acceleration\\\\Net \;force = 50 \times 3[/tex]

Net force = 150 Newton

Substituting the values into eqn 2, we have:

[tex]Frictional\; force = 600 - 150[/tex]

Frictional force = 450 Newton

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