m∠ABC=95°
Find m∠ABD and m∠DBC.
Please explain how to do this

Answer:
m∠ABD=37° and m∠DBC = 58°.
Step-by-step explanation:
Given information: m∠ABC=95°
From the given figure it is clear that m∠ABD=(2x+23)° and m∠DBC=9x-5° .
[tex]m\angle ABC=m\angle ABD+m\angle DBC[/tex]
Substitute value of each angle in the above equation.
[tex](95)^{\circ}=(2x+23)^{\circ}+(9x-5)^{\circ}[/tex]
Comparing the measure we get
[tex](95)=(2x+23)+(9x-5)[/tex]
On combining like terms we get
[tex]95=(2x+9x)+(23-5)[/tex]
[tex]95=11x+18[/tex]
Subtract 18 from both sides.
[tex]95-18=11x[/tex]
[tex]77=11x[/tex]
Divide both sides by 11.
[tex]7=x[/tex]
The value of x is 7.
[tex]m\angle ABD=(2x+23)^{\circ}=(2(7)+23)^{\circ}=37^{\circ}[/tex]
[tex]m\angle DBC=(9x-5)^{\circ}=(9(7)-5)^{\circ}=58^{\circ}[/tex]
Therefore m∠ABD=37° and m∠DBC = 58°.
The measure of m∠ABD and m∠DBC are 37 and 58degrees respectively
given that m<ABC is 95degrees
The line that bisects an angle divides the angle equally and an angle is formed from the intersection of two lines.
From the given diagram:
<ABC = <ABD + <DBC
Given te following
<ABC = 95degrees
<ABD = 2x + 23
<DBC = 9x - 5
Substitute into the equation
95 = 2x + 23 + 9x - 5
95 =11x +18
11x = 95 - 18
11x = 77
x = 77/11
x = 7
Get the angle <ABD
<ABD = 2x + 23
<ABD = 2(7) + 23
<ABD = 14 + 23
<ABD = 37degrees
Get the angle DBC
<DBC = 95 - <ABD
<DBC = 95 - 37
<DBC = 58degrees
Hence the measure of m∠ABD and m∠DBC are 37 and 58degrees respectively.
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